Test Latex

$\sqrt{x}$

$$
\begin{aligned}
3x^2-4x-5&=0
\end{aligned}
$$

Using the quadratic formula,

$$
x=\frac{-(-4)\pm\sqrt{(-4)^2-4(3)(-5)}}{2(3)}.
$$

Simplify:

$$
\begin{aligned}
x
&=\frac{4\pm\sqrt{16+60}}{6} \
&=\frac{4\pm\sqrt{76}}{6} \
&=\frac{4\pm2\sqrt{19}}{6} \
&=\frac{2\pm\sqrt{19}}{3}.
\end{aligned}
$$

Therefore,

$$
\boxed{x=\frac{2+\sqrt{19}}{3}\quad\text{or}\quad x=\frac{2-\sqrt{19}}{3}.}
$$

WP QuickLatex

$$
\begin{aligned}
3x^2+4x-5&=0
\end{aligned}
$$

Using the quadratic formula,

$$
x=\frac{-4\pm\sqrt{4^2-4(3)(-5)}}{2(3)}.
$$

Simplify:

$$
\begin{aligned}
x
&=\frac{-4\pm\sqrt{16+60}}{6}\
&=\frac{-4\pm\sqrt{76}}{6}\
&=\frac{-4\pm2\sqrt{19}}{6}\
&=\frac{-2\pm\sqrt{19}}{3}.
\end{aligned}
$$

Therefore,

$$
\boxed{x=\frac{-2+\sqrt{19}}{3}\quad\text{or}\quad x=\frac{-2-\sqrt{19}}{3}.}
$$

Try again:

[latexpage]

$$
3x^2+4x-5=0
$$

Using the quadratic formula,

$$
x=\frac{-4\pm\sqrt{4^2-4(3)(-5)}}{2(3)}.
$$

Simplify:

\begin{align} x &=\frac{-4\pm\sqrt{16+60}}{6}\ &=\frac{-4\pm\sqrt{76}}{6}\ &=\frac{-4\pm2\sqrt{19}}{6}\ &=\frac{-2\pm\sqrt{19}}{3}. \end{align}

Therefore,

$$
\boxed{
x=\frac{-2+\sqrt{19}}{3}
\quad\text{or}\quad
x=\frac{-2-\sqrt{19}}{3}
}
$$